Everything you need to build the 10-storey RC frame yourself — grid, stories, sections, loads, the four combinations, BNBC 2020 lateral parameters — plus three hand checks worked all the way to numbers so you can tell whether ETABS is doing what you think it is.
A ten-storey reinforced concrete residential building on a 60′ × 52′ footprint, with a grade beam level, a lift core shear wall, and a stair/lift machine room poking above the roof.
The work splits into three phases, and they have to happen in order. Each one feeds the next, so a mistake in phase 1 shows up as garbage in phase 3.
Grid, stories, sections, loads, combinations. Nothing is designed yet — you are just describing the building to the software.
Run it, then check three numbers by hand before you trust anything. This is the step everybody skips and it is the step that catches the errors.
Pull the design output, choose bars, and draft the column schedule and the Beam AB long section in AutoCAD.
Three bays each way. The X bays are A–B–A; the Y bays are B–16′–B, where that middle 16′ strip is the fixed 7′ + 9′ corridor from the plan and does not scale with your serial number.
| Axis | Offset | Cumulative |
|---|---|---|
| 1 | — | 0 |
| 2 | 21 | 21 |
| 3 | 18 | 39 |
| 4 | 21 | 60 |
| Axis | Offset | Cumulative |
|---|---|---|
| A | — | 0 |
| B | 18 | 18 |
| C | 16 | 34 |
| D | 18 | 52 |
Sixteen columns at the grid intersections. The highlighted node is the circled column for your schedule; Beam AB is the three-span line along the top.
Enter these in Edit › Stories and Grid Systems › Modify/Show Story Data. Build them bottom-up. Only the ten typical floors are similar to each other — make Story 1 the master and set Stories 2–10 as similar to it, which is what lets you assign loads once.
| Level | Height | Elevation | Master / similar to | Notes |
|---|---|---|---|---|
| Base | — | 0 | — | Fixed restraint, all 16 columns |
| GB | 6′-0″ | 6′-0″ | Master | Grade beams only — no slab, no veranda |
| Story 1 | 11′-0″ | 17′-0″ | Master | Beam AB lives here |
| Story 2–10 | 11′-0″ each | up to 116′-0″ | Similar to Story 1 | Typical floors |
| Lift / stair top | 7′-6″ | 123′-6″ | Master | Machine room over core only |
1. The GB level carries grade beams but no slab — if you draw a floor there, you add roughly 367 kip of dead load that does not exist. 2. The lift/stair top is not a full floor. Draw it over the core footprint only, or your seismic weight and your base shear both come out high.
Two concrete grades, one steel grade. The trap is that the slabs and stair are 4000 psi while everything else is 4500 — define both materials before you define any section.
| Material | f′c / fy | E (ksi) | Used by |
|---|---|---|---|
| CONC4500 | 4500 psi | 3824 | All columns, all beams, shear wall |
| CONC4000 | 4000 psi | 3605 | Floor slabs, stair slab |
| Gr60 | 60 ksi | 29000 | All reinforcement |
\( E_c = 57000\sqrt{f'_c} \) psi — 3824 ksi and 3605 ksi respectively. ETABS fills these in once you type f′c, but check them; a wrong E changes every drift and period you report.
Define › Section Properties › Frame Sections for the line elements, › Slab Sections and › Wall Sections for the shells.
| Name | b × h (in) | Ag (in²) | Type |
|---|---|---|---|
| C1 | 12 × 18 | 216 | Column |
| C2 | 15 × 18 | 270 | Column |
| C3 | 18 × 18 | 324 | Column |
| GB | 12 × 18 | 216 | Grade beam |
| FB | 12 × 20 | 240 | Floor beam |
| SB | 12 × 12 | 144 | Secondary beam |
| Name | t | f′c | Modelling type |
|---|---|---|---|
| SLAB5 | 5″ | 4000 | Shell — thin, membrane f11/f22 × 0.25 cracked |
| STAIR6 | 6″ | 4000 | Shell — thin |
| SW10 | 10″ | 4500 | Shell — thin, pier-labelled |
Label the core walls as piers (Assign › Shell › Pier Label) or ETABS reports wall forces element by element and you will not be able to design the core.
Sixteen columns, three section types, and a pattern that is not symmetric. This is the one part of the model you cannot infer — you have to read it off the plan.
The grid gives you sixteen intersections: four X axes × four Y axes. What it does not give you is which of C1, C2 and C3 sits at each one. The plan in your assignment has a C1 at an interior position on the second row, which breaks any rule of thumb like “corners are small, interiors are big.” If you guess, you will get a plausible-looking model that is wrong in a way nobody catches until the column schedule.
Transcribe the layout into this table from your PDF before you draw anything:
| Grid | X (ft) | Y (ft) | Section | Position |
|---|---|---|---|---|
| 1-A | 0 | 0 | from plan | Corner |
| 2-A | 21 | 0 | from plan | Edge |
| 3-A | 39 | 0 | from plan | Edge |
| 4-A | 60 | 0 | from plan | Corner |
| 1-B | 0 | 18 | from plan | Edge |
| 2-B | 21 | 18 | C3 — the circled one | Interior |
| 3-B | 39 | 18 | from plan — watch for the C1 | Interior |
| 4-B | 60 | 18 | from plan | Edge |
| 1-C … 4-C | — | 34 | from plan | Edge / interior |
| 1-D … 4-D | — | 52 | from plan | Corner / edge |
Columns are drawn once and then replicated up the building. Draw the GB-to-Story-1 lift at the grid intersections, select all of them, and use Edit › Replicate › Story to carry them to Story 10. Orientation matters for C1 and C2 since they are rectangular — the 18″ dimension normally runs parallel to the beam that frames the weaker direction, so check the plan for which way each one is turned.
Four load patterns carry gravity, and the mistake that ruins models is putting a load on the wrong kind of object — area loads onto slabs, line loads onto beams, and never both for the same physical thing.
Define › Load Patterns. Self-weight multiplier is 1 on DEAD only and 0 on everything else. If you leave it at 1 on the superimposed pattern too, you count the whole concrete frame twice.
| Pattern | Type | Self-wt mult. | What it carries |
|---|---|---|---|
| DEAD | Dead | 1 | Concrete self-weight, computed by ETABS |
| SDL | Super Dead | 0 | FF 25 psf + PW 30 psf = 55 psf on slabs |
| WALL | Super Dead | 0 | 425 lb/ft line load on wall-supporting beams |
| LIVE | Live | 0 | 40 psf floors, 100 psf stair |
| EQX / EQY | Seismic | 0 | BNBC 2020 auto-lateral |
| WX / WY | Wind | 0 | BNBC 2020 auto-lateral |
The 5″ slab weighs 62.5 psf on its own and ETABS adds that itself through DEAD. Your superimposed dead load is only the finish and partition allowance:
| Component | Value | Pattern | Applied to |
|---|---|---|---|
| Slab self-weight | 62.5 psf | DEAD (auto) | — do not enter |
| Floor finish | 25 psf | SDL | All floor slabs |
| Partition wall allowance | 30 psf | SDL | All floor slabs |
| Total slab dead load | 117.5 psf | — | — |
This is a 5″ brick wall carried on a beam. It goes on beams, not slabs, and only on the beams that actually have a wall over them: the full perimeter at every floor, plus the interior partition lines shown on your architectural plan.
| Area | Live load | Note |
|---|---|---|
| All floor slabs | 40 psf | Residential occupancy |
| Stair slab | 100 psf | Egress — applies to the 6″ stair shell |
| Roof | 40 psf | Unless your brief says otherwise |
Live load reduction: ETABS will not apply it unless you switch it on, and for a ten-storey column it makes a real difference — see Check 1, where it takes the accumulated live load from 133 kip down to 53 kip.
Define exactly these four at Define › Load Combinations. Not ETABS's auto-generated set — these specific four, with these names.
| Name | Definition | Type | What it is for |
|---|---|---|---|
| UFL | 1.0 DL + 1.0 LL | Service | Deflection, drift, unfactored reactions |
| FDL | 1.2 DL + 1.6 LL | Strength | Governing gravity case |
| FDLEQy | 0.9 DL + 1.2 LL + 1.32 EQy | Strength | Gravity + seismic, Y direction |
| FDLWx | 0.9 DL + 1.2 LL + 1.2 Wx | Strength | Gravity + wind, X direction |
Two of these are one-directional by design. FDLEQy only covers seismic in Y and FDLWx only covers wind in X, which is what the brief asks for. Be aware that means the combination set is not a complete design envelope — a real design needs EQx and Wy too, plus the negative senses of each. Say so on your sheet rather than quietly implying the four are sufficient.
For the Beam AB envelope in section 11, take the worst of FDL, FDLEQy and FDLWx at each station. Under the lateral combinations the support moments grow and can reverse sign, which is exactly why the bottom steel has to be continued into the supports.
Both are auto-lateral loads in ETABS. Enter the code parameters and let it build the storey force distribution — then check the total against section 10.
Z = 0.20 · I = 1.0 · Site Class SD
S = 1.5, TB = 0.2 s, TC = 0.8 s, TD = 2.0 s
R = choose for your system, state it
η = 1.0 at 5% damping
V = 147 mph (65.7 m/s), 3-second gust
Exposure A (urban) · I = 1.0
Kd = 0.85, Kzt = 1.0, G = 0.85
Cp = +0.8 windward, −0.5 leeward
You have a dual system: moment frames plus a lift-core shear wall. The R value depends on the detailing level you commit to, and it is a factor-of-1.3 swing in your design forces, so it is not a throwaway choice:
| System | R | Resulting V | Detailing burden |
|---|---|---|---|
| Dual — intermediate frame + ordinary RC wall | 5.5 | 620 k | Moderate; realistic for Zone 2 |
| Dual — special frame + special RC wall | 7.0 | 487 k | Full seismic detailing throughout |
Both rows assume the frames can independently resist at least 25% of the base shear, which is the defining condition for a dual system. Check that in your model by running the frames without the wall — if they cannot, it is a wall system and R drops again.
Whichever R you pick, write it on the sheet with a one-line reason. “R = 5.5, dual system with intermediate RC moment frames and ordinary RC shear walls, BNBC 2020 Table 6.2.19” is a defensible sentence. An R with no justification is the first thing a reviewer circles.
The circled C3 at grid 2-B, at ground floor, where it is carrying everything above it. This is the check that tells you whether your load assignment is right, because it depends on every pattern at once.
For a tied column the code caps the pure-axial capacity at \( \phi P_{n,max} = 0.80\phi[0.85f'_c(A_g - A_{st}) + f_y A_{st}] \) with \(\phi = 0.65\). At \(A_g\) = 324 in²:
Pull the axial force at the base of the 2-B column under FDL. It should land in the 780–870 kip band. Over that band means you have doubled a load somewhere — usually self-weight on two patterns, or a slab drawn at the GB level. Well under it means a pattern is not reaching the slab, or live load reduction is set more aggressively than the hand calc.
Beam AB runs along the top grid line, Y = 52′, at Story 1. Three continuous spans of 21′ – 18′ – 21′, section FB 12×20.
The ACI approximate moment coefficients are legitimate here, and worth using because they give you an independent number that owes nothing to your model. Check the conditions first — all four hold:
| Condition | This beam | OK? |
|---|---|---|
| Two or more spans | Three | ✓ |
| Adjacent spans differ by ≤ 20% | 21 vs 18 → 14.3% | ✓ |
| Loads uniformly distributed | Slab + wall, both uniform | ✓ |
| Unfactored L/D ≤ 3 | 0.19 | ✓ |
| Location | Coefficient | Mu (k-ft) | As req (in²) | Bars |
|---|---|---|---|---|
| −M exterior support | wuln²/16 | 50.6 | 0.70 | 2-#6 |
| +M end span (21′) | wuln²/14 | 57.8 | 0.76 | 2-#6 |
| −M first interior support | wuln²/10 | 69.0 | 0.91 | 2-#7 |
| +M middle span (18′) | wuln²/16 | 33.4 | 0.70 | 2-#6 |
\(A_s\) from \(R_n = M_u/\phi bd^2\) with \(d\) = 17.5″, then \(\rho = \dfrac{0.85f'_c}{f_y}\left(1-\sqrt{1-\dfrac{2R_n}{0.85f'_c}}\right)\). Minimum steel \(\rho_{min} = 3\sqrt{f'_c}/f_y = 0.00335\) governs three of the four locations — \(A_{s,min}\) = 0.70 in².
\( \phi V_c = 0.75 \times 2\sqrt{f'_c}b_wd = \) 21.1 kip, against a maximum \(V_u\) of 23.9 kip at the face of the first interior support. Stirrups are needed but the demand is small — \(V_s\) required is only 3.6 kip, so the maximum spacing \(d/2\) governs everywhere.
The global check. If your seismic weight is wrong, everything lateral is wrong, and this catches it in five minutes.
Floor area is 3120 ft². Build the weight up component by component for one typical floor:
| Component | Basis | kip / floor |
|---|---|---|
| Slab + finishes | 117.5 psf over the plan area | 366.6 |
| Beams | 0.1875 k/ft stem, all grid lines | 84.0 |
| Columns | 16 columns, average 15×18 | 49.5 |
| Brick walls | 0.425 k/ft, perimeter + partitions | 146.2 |
| Lift core wall | 10″ wall, ~26 ft net length | 35.8 |
| W per floor | 219 psf | 682 |
| W total | 10 floors | 6,821 |
Seismic base shear should land somewhere around 5–9% of W, i.e. roughly 340–620 kip depending on the R and the period you end up with. Wind is smaller but not negligible at 326 kip. Compare both against your ETABS auto-lateral totals under Display › Load Cases › Base Reactions.
This is what the AutoCAD long section has to show: where the bars are, where they stop, and why they stop there.
Pull the moment envelope from ETABS first. Take the worst of FDL, FDLEQy and FDLWx at every station along the beam, not just the FDL diagram — under the lateral combinations the support moments grow and the end-span support moment can reverse.
Top steel over the supports, bottom steel in the spans, and the cut-off distances measured from each support face. Dimensions update with your span lengths.
| Bar | Rule | This beam |
|---|---|---|
| Top, interior support | Extend ln/4 past the face each side | 4′-11″ |
| Top, into the 18′ span | ln/4 of the shorter span | 4′-2″ |
| Top, exterior support | ln/5, hooked into the column | 3′-11″ |
| Bottom, into support | At least ¼ of +As continuous, 6″ min into the support | 2-#6 through |
| Development, #7 top | ld, top-bar factor ψt = 1.3 | 4′-3″ |
| Development, #6 bottom | ld, ψs = 0.8 | 1′-9″ |
| Standard hook, #7 | ldh, 90° hook | 1′-1″ |
Extend every bar a distance \(d\) or \(12d_b\) beyond the point where it is no longer needed for flexure — here that is 17.5″ and 10.5″ for a #7, so 17.5″ governs. And at least one third of the negative steel must run past the inflection point by \(d\), \(12d_b\), or \(l_n/16\), whichever is greatest. Show both on the drawing; markers are what the checker looks for.
Four drawings, and each one has a specific job. Draw them at a real scale in model space and plot through a layout — do not draw to fit the paper.
Grid with dimensions, all sixteen columns with their section marks, beam marks on every line, slab panel callouts. Scale 1/8″ = 1′-0″. This is the drawing that proves your column layout matches the architectural plan.
The circled column, storey by storey: section size, bar count and size, tie size and spacing, and the splice location. One row per storey group. Include the load it was designed for so the numbers are traceable.
Three spans at 1/4″ = 1′-0″ horizontal. Top and bottom bars with cut-off dimensions, stirrup zones and spacings, support faces marked. Add the moment envelope above it at the same horizontal scale so the steel visibly follows the moment.
Cut through the beam at midspan and at a support, 1″ = 1′-0″. Two sections, because the bar arrangement is different at each — that difference is the whole point of the drawing.
| Layer | Colour | Lineweight | Contents |
|---|---|---|---|
| S-GRID | Grey 8 | 0.09 | Grid lines, bubbles |
| S-CONC | Cyan 4 | 0.35 | Concrete outlines |
| S-REBAR | Red 1 | 0.50 | Main bars — heaviest line on the sheet |
| S-STIRRUP | Green 3 | 0.25 | Stirrups, ties |
| S-DIM | Yellow 2 | 0.13 | Dimensions, leaders |
| S-TEXT | White 7 | 0.18 | Notes, bar callouts |
Annotate every bar as count – size – length, for example 2-#7 × 12′-6″, and give each a bar mark that matches a bar bending schedule on the same sheet. A drawing with bars but no schedule cannot be fabricated from.
A 15% gap between hand check and model is normal. Beyond that, it is almost always one of these six things, roughly in order of how often it happens.
| # | Symptom | Cause | Fix |
|---|---|---|---|
| 1 | Everything is ~50% heavy | Self-weight multiplier left at 1 on SDL as well as DEAD | Set SDL and WALL multipliers to 0 |
| 2 | Base reaction high by ~360 kip | A slab drawn at the GB level | Delete it — GB carries beams only |
| 3 | Beam moments low by ~25% | WALL pattern missing from the combinations | DL means DEAD + SDL + WALL, three rows each |
| 4 | Column axial low | Slab not meshed, so load never reaches the beams | Auto-mesh the floor, or check the load path |
| 5 | Base shear high, drift tiny | Property modifiers left at 1.0 | Apply cracked-section modifiers |
| 6 | Wall forces unusable | Core walls not pier-labelled | Assign pier labels to the whole core |
Always start with the total base reaction under DEAD alone and compare it to 6800 kip ± 10% for a building this size. That one number catches causes 1, 2 and 4 immediately. Only once the gravity total is right does it make sense to look at individual members.